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Calling
.contiguous()here is a good safeguard to ensure theprobstensor meets the memory layout requirements of thetop_k_top_p_sampling_from_probskernel, which is likely a custom C++/CUDA kernel fromsgl_kernelthat expects contiguous inputs. This prevents potential runtime errors or incorrect behavior ifprobsbecomes non-contiguous due to upstream operations.To improve code clarity and maintainability, consider adding a brief inline comment explaining why this call is necessary. This helps future developers understand the requirement, especially since
.contiguous()can incur a performance overhead if a copy is made.For example: