URL to the section(s) of the book with this problem:
https://doc.rust-lang.org/book/appendix-02-operators.html#operators
Description of the problem:
There is a slight inconsistency in Table B-1, which lists Rust's operators with short examples for context. In this table, var is used as a stand-in for the LHS of assignment operators (as in var += expr). However, it's also used in the example for != (var != expr). This does not match the other non-assigning operators (== has the example expr == expr) and could give the mistaken impression that != is an assignment operator.
Suggested fix:
Change the example for != from var != expr to expr != expr, which will make it consistent with the rest of the table and avoid giving the impression that != assigns to the LHS.
mainbranch to see if this has already been fixedURL to the section(s) of the book with this problem:
https://doc.rust-lang.org/book/appendix-02-operators.html#operators
Description of the problem:
There is a slight inconsistency in Table B-1, which lists Rust's operators with short examples for context. In this table,
varis used as a stand-in for the LHS of assignment operators (as invar += expr). However, it's also used in the example for!=(var != expr). This does not match the other non-assigning operators (==has the exampleexpr == expr) and could give the mistaken impression that!=is an assignment operator.Suggested fix:
Change the example for
!=fromvar != exprtoexpr != expr, which will make it consistent with the rest of the table and avoid giving the impression that!=assigns to the LHS.