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Add performance test #275
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Add performance test #275
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8425756
add performance test
jagerber48 b3e66a1
try codspeed
jagerber48 d532874
process time for complexity
jagerber48 c6c6128
test complexity
jagerber48 992a37a
codspeed CI
jagerber48 4153cf2
adjust test running
jagerber48 d0120b3
adjust test more
jagerber48 2dd07b9
only run on latest ubuntu
jagerber48 4480808
slightly different ufloat summation
jagerber48 c19d373
comments
jagerber48 a052ae1
Merge remote-tracking branch 'origin/feature/benchmark_test' into fea…
jagerber48 c9b46a5
benchmark multiple N values
jagerber48 5f4d55a
reverse order of decorators
jagerber48 f98349e
benchmark fixture?
jagerber48 eb29951
run the benchmark directly, maybe codspeed will handle benchmarking.
jagerber48 6470a24
refactor and clean up the tests
jagerber48 afa1712
Changelog
jagerber48 6927711
Update test_performance.py
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| Original file line number | Diff line number | Diff line change |
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| @@ -0,0 +1,57 @@ | ||
| from math import log10 | ||
| import time | ||
| import timeit | ||
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| import pytest | ||
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| from uncertainties import ufloat | ||
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| def repeated_summation(num): | ||
| """ | ||
| generate and sum many floats together, then calculate the standard deviation of the | ||
| output. Under the lazy expansion algorithm, the uncertainty remains non-expanded | ||
| until a request is made to calculate the standard deviation. | ||
| """ | ||
| result = sum(ufloat(1, 0.1) for _ in range(num)).std_dev | ||
| return result | ||
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| def test_repeated_summation_complexity(): | ||
| """ | ||
| Test that the execution time is linear in summation length | ||
| """ | ||
| approx_execution_time_per_n = 10e-6 # 10 us | ||
| target_test_duration = 1 # 1 s | ||
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| n_list = [10, 100, 1000, 10000, 100000] | ||
| t_list = [] | ||
| for n in n_list: | ||
| """ | ||
| Choose the number of repetitions so that the test takes target_test_duration | ||
| assuming the timing of a single run is approximately | ||
| N * approx_execution_time_per_n | ||
| """ | ||
| # Choose the number of repetitions so that the test | ||
| single_rep_duration = n * approx_execution_time_per_n | ||
| num_reps = int(target_test_duration / single_rep_duration) | ||
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| t_tot = timeit.timeit( | ||
| lambda: repeated_summation(n), | ||
| number=num_reps, | ||
| timer=time.process_time, | ||
| ) | ||
| t_single = t_tot / num_reps | ||
| t_list.append(t_single) | ||
| n0 = n_list[0] | ||
| t0 = t_list[0] | ||
| for n, t in zip(n_list[1:], t_list[1:]): | ||
| # Check that the plot of t vs n is linear on a log scale to within 10% | ||
| # See PR 275 | ||
| assert 0.9 * log10(n / n0) < log10(t / t0) < 1.1 * log10(n / n0) | ||
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| @pytest.mark.parametrize("num", (10, 100, 1000, 10000, 100000)) | ||
| @pytest.mark.benchmark | ||
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| def test_repeated_summation_speed(num): | ||
| repeated_summation(num) | ||
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I've seen a test similar to this that kept randomly failing so I don't know how reliable this test will be.
I think test_repeated_summation_speed will catch any increases in time so these tests are testing the same thing. I'm not opposed to this test- we can leave it in for now, and if it we find it unreliable we can remove it.
I'll add a link to PR with the graph you plotted as it helps makes sense of this test. It'll be good to see this plotted for your other PR too.