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Training exercise. #7

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125 changes: 99 additions & 26 deletions problem-solving/Program.cs
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Original file line number Diff line number Diff line change
Expand Up @@ -16,85 +16,125 @@ static void Main(string[] args)
public static long SumArray(IEnumerable<int> arr)
{
// return the sum of all the values in the array
// TODO
return 0;
return Array.ConvertAll(arr.ToArray(), x => (long)x).Sum();
}

public static long SumArrayOddValues(IEnumerable<int> arr)
{
// return the sum of all the values in the array that are odd
// TODO
return 0;
return arr.Where(x => x % 2 == 1 || x % 2 == -1).Sum();
}

public static long SumArrayEverySecondValue(IEnumerable<int> arr)
{
// return the sum of every second value in the array. i.e. the 2nd value + the 4th value + the 6th value ...
// TODO
return 0;
long sum = 0;

for (int i = 1; i < arr.Count(); i += 2)
sum += arr.ElementAt(i);

return sum;
}

public static IEnumerable<int> GetUniqueValues(IEnumerable<int> arr)
{
// return an array that contains only unique values from the passed in array
// TODO
return null;
return arr.Distinct();
}

public static IEnumerable<int> GetArrayIntersect(IEnumerable<int> arrA, IEnumerable<int> arrB)
{
// return an array that contains all the values that are in array A and array B
// TODO
return null;
return arrA.Intersect(arrB);
}

public static IEnumerable<int> GetArrayNotIntersect(IEnumerable<int> arrA, IEnumerable<int> arrB)
{
// return an array that contains all the values that are in array A or array B but not in both array A and array B
// TODO
return null;
return arrA.Distinct().Except(arrB.Distinct());
}

public static Boolean HasSum(IEnumerable<int> arr, long target)
{
// return true if any 2 values in the array have a sum equal to the target value
// TODO
if (arr == null)
throw new NullReferenceException("The passed in value was null and could not be interpreted");

int[] values = arr.ToArray<int>();

for (int i = 0; i < arr.Count() - 1; i++)
for (int j = arr.Count() - 1; j > 0; j--)
if (values[i] + values[j] == target)
return true;

return false;
}

public static long LoneSum(IEnumerable<int> arr)
{
// Given an array of int values, return their sum.
// However, if any of the values is the same as another of the values, it does not count towards the sum.
return 0;
if (arr == null)
throw new ArgumentNullException("The passed in value was null and could not be interpreted");

long sum = 0;

foreach (int i in arr)
if (arr.Count(x => x==i) == 1)
sum += i;

return sum;
}

public static String DoubleString(String s)
{
// return a string that is the original string with each character in the string repeated twice
// e.g. for input "ABCDE", return "AABBCCDDEE"
return null;
if (s == null)
throw new ArgumentNullException("The passed in value was null and could not be interpreted");

string output = String.Empty;

foreach (char c in s.ToCharArray())
output += c.ToString() + c.ToString();

return output;
}

public static int CountChars(String s, char c)
{
// return the count of how many times char c occurs in string s
return 0;
if (s == null)
throw new ArgumentNullException("The passed in value was null and could not be interpreted");

return s.ToCharArray().Where(x => x.Equals(c)).Count();
}

public static long SumDigits(String s)
{
// return the sum of the digits 0-9 that appear in the string, ignoring all other characters
// e.g. "123" return 6
return 0;
long sum = 0;
s = Regex.Replace(s, @"[\D]", string.Empty);

foreach (char c in s)
sum += int.Parse(c.ToString());

return sum;
}

public static long SumNumbers(String s)
{
// return the sum of the numbers that appear in the string, ignoring all other characters
// a number is a series of 1 or more digits in a row
// e.g. "11 22" returns 33
return 0;
long sum = 0;
String[] digits = Regex.Matches(s, @"[\d]+").Cast<Match>().Select(x => x.Value).ToArray<String>();

foreach (string digit in digits)
sum += int.Parse(digit);

return sum;
}

public static Boolean IsAnagram(String s1, String s2)
Expand All @@ -103,53 +143,86 @@ public static Boolean IsAnagram(String s1, String s2)
// An anagram is produced by rearranging the letters of one string into another
// e.g. care is an anagram of race
// cat is not an anagram of rat
return false;
IOrderedEnumerable<char> string1Characters = s1.ToLower().OrderBy(x => x);
IOrderedEnumerable<char> string2Characters = s2.ToLower().OrderBy(x => x);

return (string1Characters.SequenceEqual(string2Characters));
}

public static int BlackJack(int count1, int count2)
{
// Given 2 integer values greater than 0,
// return whichever value is nearest to 21 without going over.
// Return 0 if they both go over.
return 0;
int[] arr = { count1, count2 };

return NPlayerBlackJack(arr);
}

public static int FivePlayerBlackJack(int count1, int count2, int count3, int count4, int count5)
{
// Given 5 integer values greater than 0,
// return whichever value is nearest to 21 without going over.
// Return 0 if they all go over.
return 0;
int[] arr = {count1, count2, count3, count4, count5};

return NPlayerBlackJack(arr);
}

public static int NPlayerBlackJack(IEnumerable<int> counts)
{
// Given a list of integer values greater than 0,
// return whichever value is nearest to 21 without going over.
// Return 0 if they all go over.
return 0;
if (counts.Where(x => x <= 21).Count() == 0)
return 0;
else
return counts.ToArray().Where(x => x <= 21).Max(); ;
}

public static Dictionary<String, int> WordCount(IEnumerable<String> arr)
{
// Given an array of Strings,
// return a dictionary keyed on the string with the count of how many times each string appears in the array
return null;
Dictionary<String, int> counts = new Dictionary<string,int>();

foreach (string word in arr)
if (counts.ContainsKey(word))
counts[word]++;
else
counts.Add(word, 1);

return counts;
}

public static int Factorial(int n)
{
// Given n of 1 or more, return the factorial of n, which is n * (n-1) * (n-2) ... 1
return 0;
if (n <= 1)
return 1;
return n * Factorial(n - 1);
}

public static List<String> FB(int n)
public static String[] FB(int n)
{
// Given n, print the numbers from 1 to n as a string to a List of strings, with the following exceptions:
// If the number is divisable by 3, replace it with the word "Fizz"
// If the number is divisable by 5, replace it with the word "Buzz"
// If the number is divisable by both 3 and 5, replace it with the word "FizzBuzz"
return null;
List<String> results = new List<string>();
for (int i = 1; i <= n; i++)
{
if (i % 15 == 0)
results.Add("FizzBuzz");
else if (i % 5 == 0)
results.Add("Buzz");
else if (i % 3 == 0)
results.Add("Fizz");
else
results.Add(i.ToString());
}

return results.ToArray();
}
}
}