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42 changes: 38 additions & 4 deletions arrow-ord/src/partition.rs
Original file line number Diff line number Diff line change
Expand Up @@ -21,9 +21,10 @@ use std::ops::Range;

use arrow_array::{Array, ArrayRef};
use arrow_buffer::BooleanBuffer;
use arrow_schema::ArrowError;
use arrow_schema::{ArrowError, SortOptions};

use crate::cmp::distinct;
use crate::ord::make_comparator;

/// A computed set of partitions, see [`partition`]
#[derive(Debug, Clone)]
Expand Down Expand Up @@ -156,18 +157,24 @@ fn find_boundaries(v: &dyn Array) -> Result<BooleanBuffer, ArrowError> {
let slice_len = v.len() - 1;
let v1 = v.slice(0, slice_len);
let v2 = v.slice(1, slice_len);
Ok(distinct(&v1, &v2)?.values().clone())

if !v.data_type().is_nested() {
return Ok(distinct(&v1, &v2)?.values().clone());
}
// Given that we're only comparing values, null ordering in the input or
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I wonder if using eq would be faster 🤔

https://docs.rs/arrow/latest/arrow/compute/kernels/cmp/fn.eq.html

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Do you mean for non-nested types? eq doesn't support nested types similarly to distinct and given they both shell out to compare_op I don't think there should be much of a perf difference between distinct and eq + mapping nulls to booleans (which would be necessary).

// sort options do not matter.
let cmp = make_comparator(&v1, &v2, SortOptions::default())?;
Ok((0..slice_len).map(|i| !cmp(i, i).is_eq()).collect())
}

#[cfg(test)]
mod tests {
use std::sync::Arc;

use super::*;
use arrow_array::*;
use arrow_schema::DataType;

use super::*;

#[test]
fn test_partition_empty() {
let err = partition(&[]).unwrap_err();
Expand Down Expand Up @@ -298,4 +305,31 @@ mod tests {
vec![(0..1), (1..2), (2..4), (4..5), (5..7), (7..8), (8..9)],
);
}

#[test]
fn test_partition_nested() {
let input = vec![
Arc::new(
StructArray::try_from(vec![(
"f1",
Arc::new(Int64Array::from(vec![
None,
None,
Some(1),
Some(2),
Some(2),
Some(2),
Some(3),
Some(4),
])) as _,
)])
.unwrap(),
) as _,
Arc::new(Int64Array::from(vec![1, 1, 1, 2, 3, 3, 3, 4])) as _,
];
assert_eq!(
partition(&input).unwrap().ranges(),
vec![0..2, 2..3, 3..4, 4..6, 6..7, 7..8]
)
}
}
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