*** weak 1 ***
A mathematical program that is not an LP.
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Dividing by variables is not allowed. $$ \bold{-1/x_1} - x_3 $$
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Cannot have strict inequalities.
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Must have finite number of constraints.
An integer program is a linear program with added integrality constraints for some/all of the variables. $$ max:\ x_1 + x_2 +2x_4 \ s.t.\ \ \ x1+x2\leq 1 \ -x_2 - x_3 \geq -1 \ x_1 + x_3 = 1 \ \ \ x_1, x_2, x_3 \geq 0 \ \quad \bold{x1, x3 \ integer.} $$ Note LPs are easy to solve, IPs are not.
*** weak 2** *
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when y1 = 0, x1 = 0;
when y1 =1, 1000<=x1<=M; $$ Give \ L(y1)<=x1<=U(y1), \ 1000y1 \leq x1 \leq My1 $$
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If x3 >= 500, then x2 <= 400; $$ Z = \begin{cases} 1, & 500 \leq x_3 \leq 6000 & and & 0 \leq x_2\leq 400\ 0, & 0 \leq x_3 \leq 499 & and & 0\leq x_2 \leq10000 \end{cases} \ 500Z \leq x_3 \leq 6000Z + 499(1-Z) \ 0 \leq x_2 \leq 400(Z)+10000(1-Z) $$
*** weak 4 ***
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**Proving Infeasibility **
find a
$y^T$ where$y^T$Ax = $y^T$b
$y^TA \geq 0 \ y^T b < 0$
find a set of feasible solutions x(t).
*** weak 5 ***
Step 1:
Step 2: convert to Auxp
$$
max (1, 4, 2, 3)x \
\begin{pmatrix}
1 & -2 &2& 9 \
1 & 5 & 4 & 3
\end{pmatrix} x =
\begin{pmatrix}
-5 \
6
\end{pmatrix} \ \
\ \
converting \ to \ Auxp \
\ max (0, 0, 0, 0, -1, -1)x \
\begin{pmatrix}
-1 & 2 &-2& -9 &1 &0 \
1 & 5 & 4 & 3 &0 & 1
\end{pmatrix} x =
\begin{pmatrix}
5 \
6
\end{pmatrix} \ \
\ \
$$
Step 3: use Simplex Algorithm.
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Aux is always feasible (
$b \geq 0$ ) -
Aux objective function always bounded up by 0
Eg. (0 0 0 0 -1 -1)
$\leq$ 0Therefore, Aux always has optimal solution.
-
if opt value = 0, Aux Problem feasible, with a feasible basis.
else if opt value < 0, Aux Problem Infeasible.



